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The relationship between mAs and exposure is


A) exponential.
B) directly proportional.
C) indirectly proportional.
D) a squared relationship.

E) A) and D)
F) B) and C)

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An acceptable radiograph was taken using 20 mAs at 70 kVp at a distance of 40 inches.A second radiograph is requested at 72 inches.What mAs should be used to produce this radiograph with a 72-inch distance?

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A radiograph is taken at 400 mA, 55 ms, 95 kVp.A second image could be taken to improve contrast at


A) 400 mA, 0.110 sec, 80 kVp.
B) 400 mA, 0.055 sec, 110 kVp.
C) 500 mA, 4 ms, 95 kVp.
D) 600 mA, 0.083 sec, 92 kVp.

E) B) and C)
F) All of the above

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If 1 ampere equals a flow of 6.3 * 1018 electrons per second, how many electrons flow from cathode to anode in 1 milliampere?


A) 6.3 * 1021
B) 6.3 * 1018
C) 6.3 * 1015
D) 6.3 * 1016

E) B) and C)
F) A) and B)

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If 1 coulomb is equal to 6.3 *1018 electron charges, how many electrons flow from cathode to anode in 1 second?


A) 6.3 * 1018
B) 6.3 * 108
C) 6.3 * 104
D) 6,300

E) A) and C)
F) B) and C)

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As the mA doubles, the number of electrons flowing from cathode to anode


A) increases fourfold.
B) increases twofold.
C) decreases twofold.
D) increases by 50%.

E) A) and B)
F) A) and C)

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The reaction of a photographic film to light is equal to the product of the intensity of the light and the duration of the light exposure.This concept is known as


A) the reciprocity law.
B) the inverse square law.
C) Coulomb's law.
D) the 15 percent rule.

E) B) and C)
F) A) and D)

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If kVp is doubled, the amount of x-ray photons created approximately increases


A) twofold.
B) threefold.
C) fourfold.
D) eightfold.

E) A) and B)
F) A) and C)

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Given an exposure time of 0.15 second and a milliamperage of 100, calculate the mAs.

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The product of tube current and exposure time is equal to


A) kVp.
B) x-ray beam quality.
C) x-ray beam quantity.
D) the HVL.

E) None of the above
F) All of the above

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Increasing the kVp for an exposure will


A) create a decrease in the number of electrons traveling from cathode to anode.
B) decrease the speed of electrons going from cathode to anode.
C) create an increase in the number of electrons traveling from cathode to anode.
D) cause the electrons to travel faster from cathode to anode.

E) A) and D)
F) A) and C)

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Given 40 mA and an exposure time of 0.20 second, calculate the mAs.

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An acceptable radiograph was taken using 12 mAs at 80 kVp at a distance of 72 inches.To reduce the image density by 50%, the new distance should be what?

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A radiographer takes an initial radiograph using the technical factors of 50 mA at 0.46 sec.There is involuntary motion on the radiograph, but the radiographer wants to maintain radiographic film density.If the exposure time is reduced to 0.115 sec, what is the new mA?

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The factors that affect x-ray emission under the direct control of the radiographer are called the ____ factors.


A) quality
B) quantity
C) prime
D) principal

E) B) and D)
F) C) and D)

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The density maintenance formula is a


A) reciprocity law.
B) inverse square law.
C) direct square law.
D) 15 percent rule.

E) C) and D)
F) All of the above

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An x-ray exposure of 100 mR is recorded at a distance of 40 inches.To reduce the exposure to 25 mR, to what will the distance need to be changed?

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Given 25 mAs and a milliamperage of 100, calculate the exposure time.

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Kilovoltage is the primary controlling factor of


A) radiographic film density.
B) radiographic film contrast.
C) beam quantity.
D) none of the above

E) None of the above
F) A) and D)

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The length of the exposure time (S) for a radiograph, is used to primarily control


A) image contrast.
B) motion.
C) radiographic image density.
D) patient dose.

E) A) and B)
F) A) and C)

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